Sqrt(1-x^2) integral
Indefinite integral integral sqrt(1 – x^2) dx = 1/2 (sqrt(1 – x^2) x + sin^(-1)(x)) + constant Expanded form of the integral 1/2 sqrt(1 – x^2) x + 1/2 sin^(-1)(x) + constant Series expansion of the integral at x=-1 -pi/4 + 2/3 sqrt(2) (x + 1)^(3/2) – (x + 1)^(5/2)/(5 sqrt(2)) + O((x + 1)^(7/2)) (Puiseux series) Series expansion of the integral at x=0 x – x^3/6 – x^5/40 – x^7/112 + O(x^9) (Taylor series) Series expansion of the integral…